A Study Showed 118 Instances Of Breast Cancer

A study showed 118 instances of summit fecescer among 3,033 mothers who used diethylstilbestrol (DES), an estrogen-like sum of money formerly used to prevent miscarriage, compared with 80 cases in 3,033 unexposed women comprising a control group (See Table 10.1). At the .01 level of significance, was the coitus incidence of cancer greater in the DES users? display panel 10.1 crabby person Study Results Statistic DES Takers Non-DES Takers Number of cancers x1 = 118 cancers x2 = 80 cancers Number of mothers n1 = 3,033 women n2 = 3,033 women cancer rate p1 = 118 p2 = 80 3,033= .03891 3,033= .02638 criterion 1: landed estate the Hypotheses Because it is surmise that DES increases the cancer risk, we will do a r ight-tailed riddle for equality of isotropys. We test only at the equality because rejecting H0: ?1 = ?2 would imply rejecting the entire section of hypotheses H0: ?1 ? ?2.We can state the pair of hypotheses in each of twain like ways: H0: ?1 = ?2 or H0: ?1 ?2 = 0 H1: ?1 > ?2 or H1: ?1 ?2 > 0 Step 2: State the Decision Rule At ? = .01 the right-tail critical nourish is z.01 = 2.

326, which yields the decisiveness rule Reject H0 if z > 2.326 Otherwise do not reject H0 Step 3: Calculate the Test Statistic The demonstrate out proportions indicate that DES-users have a higher incidence of breast cancer (.0 3891) than non-DES users (.02638). We assume! that ?1 = ?2 and hold if a contradiction stems from this assumption. take for granted that ?1= ?2, we can kitten the two samples to obtain a pooled estimate of the common proportion by dividing the unite number of breast cancer cases by the combined sample size: .p= x1 + x2 = 118 + 80 = 198 = .03264, or 3.26% n1 + n2 3,033 + 3,033 6,066 Assuming due north (i.e., large samples) the test statistic is z = p1 ? p2 _...If you insufficiency to get a full essay, order it on our website: OrderEssay.net

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